Answer:
well
Step-by-step explanation:
why the hell would troy want to do that when he could really just go home and play fortnite
Answer:
Perpendicular!
Step-by-step explanation:
If they were parallel they would have the exact same slope. If they are perpendicular their slopes would be opposite reciprocals of each other... which they are. Another trick to tell if two slopes are perpendicular is to multiply them by each other and if the answer equals -1 they are perpendicular:
7/8 • -8/7 = -1/1 = -1
First we calculate the ambio rate from x = 0 to x = 15:
We have:
R = ((80-10) / (0-15))
R = -4.666666667
We now calculate for the entire interval:
from x = 0 to x = 20:
R = ((80-2) / (0-20))
R = -3.9
Answer:
What is the average rate of change over the entire slide?
R = -3.9
The average rate of change from x = 0 to x = 15 is about -4.667. How does the average rate change from x = 0 to x = 20 compare to this number?
The percentage difference is:
(-3.9 / -4.666666667) * (100) = 83.57142857%
100-83.57142857 = 16.42857143%
1. so it has to have every x is one y and every y has one x
graph them
we see that the only ones that are one to one are the first one, the 2nd one and the 4th one
2.
solve for x and replace with f⁻¹(x) and y with x
minus 8 and cube both sides
(y-8)³=x-2
add 2
(y-8)³+2=x
replace
f⁻¹(x)=(x-8)³+2
first one
3.
this is a one to one function because theer is no vertical line that could intersect the graph more than once
ah, I see, you're program has a different one to one definition, no horizontal or vertical line can cross, lemme edit te first question again
answer is 2nd option
4. a neat trick is this:
the domain of f(x) is the range of f⁻¹(x)
the range of f(x) is the domain of f⁻¹(x)
the domain of f(x)=1/(3x+2)
hmm, can't divide by 0 so set denomenator to 0
3x+2=0
3x=-2
x=-2/3
domain is all real numbers except -2/3
(-infinity,-2/3)U(-2/3,infinity)
that's the range of f⁻¹(x)
range
ok, hmm, range is from positive initny to 0 then from 0 to positive inifnty, not including 0
so the domain of f⁻¹(x) is (-∞,0)U(0,∞)
range of f⁻¹(x) is (-∞,-2/3)U(-2/3,∞)
first option
