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Marysya12 [62]
3 years ago
12

X^2+7x-30 Factor the quadratic Show steps

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

(−3)(+10P)

Step-by-step explanation:

in pic

(Hope this helps can I pls have brainlist (crown) ☺️)

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List three integers and their opposites?
gulaghasi [49]
-1 1, -2 2, 3 -3. Is this what you wanted? If no tell me in comments and maybe a can help fix.
4 0
3 years ago
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Butyric acid ( c3h7cooh) is a weak acid . what is the ph of a 0.0250 m solution of this acid. ka = 1.5 x 10-5 (2 decimal places)
Wewaii [24]

The pH of the weak acid is 3.21

Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

Ma = 0.0250M

Ka = 1.5 x 10¯⁵

By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

[H+] = √(1.5 x 10¯⁵ . 0.0250)

[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

pH = -log[H+]

pH = -log(6.12 x 10¯⁴)

pH = 3.21

Hence, the pH of the weak acid c3h7cooh is 3.21

Find more on pH at: brainly.com/question/14466719

#SPJ4

8 0
1 year ago
Julie is 3 years older than her sister. Julie's age is 11 years old.<br> How old is her sister?
Ne4ueva [31]

Answer:

14 :)

Step-by-step explanation:

4 0
3 years ago
In the data set below, what is the interquartile range?<br> 7<br> 1<br> 5<br> 5<br> 9<br> Submit
Marizza181 [45]

Answer:

5

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1  5  5  7  9 ← data in ascending order

       ↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1  5

 ↑ lower quartile = \frac{1+5}{2} = 3

The upper quartile is the middle value of the data to the right of the median.

7  9

 ↑ upper quartile = \frac{7+9}{2} = 8

Thus

interquartile range = 8 - 3 = 5

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3 years ago
Graph the line with slope -1/2 passing through the point (5,-3)
valkas [14]

Step-by-step explanation:

The graph is shown in the image above.

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1 year ago
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