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White raven [17]
3 years ago
6

What type of chemical reaction is this? CH4 + O2 + CO2 + H20 ?

Chemistry
1 answer:
klio [65]3 years ago
5 0

Answer:

combustion reaction. hope this helps!

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What is the scale factor?
professor190 [17]

Answer:

Scale Factor: 1 : 2

X = 11

Explanation:

3 / 3 = 1

6 / 3 = 2

The scale factor should be 1:2

So 'X' should be 11 since 5.5 * 2 = 11

4 0
4 years ago
An object sliding along a horizontal table is an example of projectile motion.
Mumz [18]
True because if anything is moving it is in motion. And because horizontal is similar to projectile!
5 0
3 years ago
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What is the (H+), if the pH of a solution is 3.20?
almond37 [142]

First of all, the answer has 3 places of accuracy.

The formula for pH is

pH = - log[H+]

Given: Ph = 3.20

Solution

3.20 = - log[H+]

Divide by - 1

-3.20 = log[H+]

Take the antilog of both sides

10^-3.20 = [H+]

[H+]= 6.30 * 10^-4 moles/L This is a measure of concentration.

It can also be written as 0.000630 moles/L

8 0
3 years ago
How many atoms are in 5.5 dozen atoms
Sergeeva-Olga [200]

Answer: 66 atoms, I believe.

5.5 times 12/dozens  + 66 Atoms

Hope this helps!

6 0
3 years ago
Read 2 more answers
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
3 years ago
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