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Yuliya22 [10]
3 years ago
12

an atom of which element has the strongest attraction for electons in a chemical bond?cholorine, phosphorus, carbon, sulfur

Chemistry
1 answer:
vredina [299]3 years ago
7 0

Answer:

D) Sulphur

Explanation:

Sulphur has the strongest electromagnetivity here

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How do you calculate the number of neutrons???? please help
vladimir1956 [14]

Answer:

The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number (Z).

Explanation:

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8 0
3 years ago
Please rank the following atoms from smallest to largest: Ge, P, O
Ghella [55]
O,P,Ge ranked from atomic radius
8 0
3 years ago
The chemical formula of bromomethane is BrCH3. Which correctly describes the number of atoms of each element in bromomethane?
Anit [1.1K]

The number of atoms of each element :

C : 1 atom

H : 3 atoms

Br = 1 atom

<h3>Further explanation</h3>

Given

Bromomethane-CH₃Br

Required

The number of atoms

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

The number of atoms in a compound is generally indicated as a subscript after the atom

C : 1 atom

H : 3 atoms

Br = 1 atom

Total 5 atoms

4 0
3 years ago
3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
3 years ago
Sort these isotopes by whether they are most likely to undergo fusion or fission.
Maslowich

Answer:

Uranium-233- fission

Plutonium-239- fission

Plutonium-241- fission

Hydrogen-3 fusion

Hydrogen-1 fusion

Helium-3 fusion

Explanation:

In nuclear fission, heavy nuclear disintegrate into smaller nuclei when bombarded with particles such as neutrons. Fission reaction is common among nuclei having a high atomic number such as plutonium and uranium.

Fusion occurs between two light nuclei such as hydrogen or helium. It involves the combination of two lighter elements to give a heavier element with the release of tremendous amount of energy.

4 0
3 years ago
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