Answer:
V_avg = 0.5556 miles/min
V_avg = 0.00926 miles/sec
Step-by-step explanation:
Bonita jogs 2.5 miles west of Vinces' house to school. It took her 15 minutes to arrive.
Speed 1; distance/time = V1 = 2.5/15 = 1/6 miles/min
Furthermore she ran 5 miles to the discount store for personal supplies. This took her 5 minutes.
Thus;
Speed 2; V2 = 5/5 = 1 mile/min
She then slowly walks back to school, which takes her another 10 minutes. Distance from the discount stor to school is 5 miles as stated in speed 2.
Thus;
Speed 3: V3 = 5/10 = ½ mile/min
Her average speed is;
V_avg = (V1 + V2 + V3)/3
V_avg = (1/6 + 1 + ½)/3
V_avg = 10/18 = 0.5556 miles/min
Converting to miles/seconds
60 seconds make 1 minutes, therefore 1 mile/min = 1/60 miles/seconds
Thus;
V_avg = 0.5556 miles/min = 0.5556 × 1/60 miles/sec = 0.00926 miles/sec
