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3 years ago

What is the range for the following set of numbers: 199, 211, 63, 200, 544, 347, 727, 98, 110 *

Mathematics

1 answer:

LenKa [72]3 years ago

8 0

Answer:

Minimum = 64

Maximum = 727

Medium = 200

Mean = 277.667

Mode = none

s = 223.825

Q = 211.024

n = 9

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13/25 as a percentage

nadezda [96]

Hi , the answer is 52% , because 13 divided by 25 equals to 0.52 , we move the decimal two spaces to the right , so the answer is 52.

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3 years ago

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kifflom [539]

Answer:

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Step-by-step explanation:

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3 years ago

You are designing an icon for a mobil app. Use the provided ruler to answer the following questions.

makkiz [27]

Answer:

a. Scale Perimeter : 2.5 centimeters

Actual Perimeter : 13 centimeters

Actual Area : 10.5 square centimeters

b. Actual Perimeter : 130 mm

Actual Area : 1,050 mm

Step-by-step explanation:

a. 2.5 mm = 0.25 cm

2 (1 + 0.25) = 2.5

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2 years ago

A researchers wants to determine the mean weight of avocados grown in Southern California. The population from which the sample

natka813 [3]

Answer: (0.465, 5.535)

Step-by-step explanation:

Formula to calculate the confidence interval (when population standard deviation is unknown) is given by :-

$\overline{x}\pm t_{\alpha/2} \dfrac{s}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

s= sample standard deviation.

n= Sample size.

$t_{\alpha/2}$ = critical value

By considering the given information , we have

$\overline{x}=6$

s=0.75

n= 9

Significance level = $\alpha=0.1$ [1-0.90=0.1]

By using students' t distribution -table , the critical value for 95% confidence level :

$t_{\alpha/2 , n-1}=t_{0.1/2,\ 8}=1.86$

[Note: degree of freedom = n-1]

Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :

$6\pm (1.86) \dfrac{0.75}{\sqrt{9}}$

$6\pm (1.86) \dfrac{0.75}{3}$

$6\pm (1.86) 0.25$

$6\pm 0.465=(6-0.465,\ 6+0.465)=(0.465,\ 5.535)$

Hence, the required confidence interval =(0.465, 5.535)

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2 years ago

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natka813 [3]

Answer:

Im pretty sure it's A because Z and AZ are collinear

6 0

2 years ago