Answer:
Partial pressure of oxygen = 23.38 kpa (Approx)
Explanation:
Given:
Amount of oxygen = 23.15%
Amount of nitrogen = 76.85%
Pressure (missing) = 101 kpa
Find:
Partial pressure of oxygen
Computation:
Partial pressure of oxygen = [Amount of oxygen x Pressure]/100
Partial pressure of oxygen = [23.15% x 101]/100
Partial pressure of oxygen = 23.38 kpa (Approx)
Answer:
Reactants, the top would be activation energy, the bottom is energy released by reaction, products
Explanation:
Explanation:
The volume of the copper block is:
The density of copper is 8.96 g/cm³
So the mass of the copper block is
or 126.44352 kg.
Answer:
<h2>The gas pressure will remain the same until the number particles remain in the range of multiple of avagadro number.</h2>
Explanation:
It will remain same until the avagadro number is achieved as the gass less than avagadro number (1 mole) will occupy same volume as the the multiple of avagadro number ( mole).
If gas is less than 1 mole it will occupy same volume as that of 1 mole.... If the number of particles are increased than the 1 mole. The gas occupy more volume consequently the pressure will be increased.
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