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Natalka [10]
2 years ago
13

Label the picture, please

Chemistry
2 answers:
DochEvi [55]2 years ago
4 0

Answer:

(in the pic above)

Explanation:

P= product

R= reactant

S= subscript

C= coefficient

Y= yields

shutvik [7]2 years ago
3 0

Answer:

sorry BUT I need points

Explanation:

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Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1
lina2011 [118]

Answer : The correct option is, (B) 273.15 K and 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

STP conditions :

The temperature is, 0^oC or 273.15K or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is 22.4 L for 1 mole of a substance.

Hence, the correct option is, (B) 273.15 K and 1 atm

7 0
3 years ago
A chemistry student weighs out of sulfurous acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distill
nadezda [96]

The question is incomplete, here is the complete question:

A chemistry student weighs out 0.104 g of sulfurous acid, a diprotic acid, into a 250.0 mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.0700 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of NaOH needed is 36.2 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of sulfurous acid = 0.104 g

Molar mass of sulfurous acid = 82 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

\text{Molarity of sulfurous acid}=\frac{0.104\times 1000}{82\times 250}\\\\\text{Molarity of sulfurous acid}=5.07\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=5.07\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.0700M\\V_2=?mL

Putting values in above equation, we get:

2\times 5.07\times 10^{-3}\times 250.0=1\times 0.0700\times V_2\\\\V_2=\frac{2\times 5.07\times 10^{-3}\times 250}{1\times 0.0700}=36.2mL

Hence, the volume of NaOH needed is 36.2 mL

5 0
3 years ago
Calculate the approximate number of atoms in a bacterium, assuming the average mass of an atom is ten times the mass of a hydrog
mezya [45]

Answer: -

The approximate number of atoms in a bacterium is 10¹¹

Explanation: -

We are given the mass of a bacterium is 10⁻¹⁵ kg.

We are told that the mass of a hydrogen atom is 10⁻²⁷ kg.

Finally we learn that the average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.

Mass of an atom of bacterium = 10 x mass of hydrogen atom

                                                   = 10 x 10⁻²⁷ kg.

                                                   = 10⁻²⁶ kg.

Thus the number of atoms in a bacterium = \frac{Total mass}{mass of 1 bacterium atom}

                                                                      = \frac{10-15 kg}{10-26 kg}

                                                                      = 10¹¹


8 0
3 years ago
Which element has the electron configuration [Rn] 7s2 5f14 6d4 ?
nexus9112 [7]

Answer:

Rn] 5f14 6d4 7s2 mp: none d: none. Seaborgium ..... Element. Density. Boiling or Melting Point in °C. Electron Configuration. Symbol.

Explanation:

3 0
3 years ago
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A second cross was done using a different pair of mice.One parent was a mouse with white fur (bb).The was other parent was a mou
eimsori [14]
Bb, or mostly dominant with a little recessive
3 0
3 years ago
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