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Natalka [10]
2 years ago
13

Label the picture, please

Chemistry
2 answers:
DochEvi [55]2 years ago
4 0

Answer:

(in the pic above)

Explanation:

P= product

R= reactant

S= subscript

C= coefficient

Y= yields

shutvik [7]2 years ago
3 0

Answer:

sorry BUT I need points

Explanation:

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How many moles are in 18.2 g of CO2?<br> 41.4 moles<br> 801 moles<br> 0.414 moles<br> 0 2.42 moles
mrs_skeptik [129]

Answer:

0.414 mole (3 sig. figs.)

Explanation:

Given grams, moles = mass/formula weight

moles in 18.2g CO₂(g) = 18.2g/44g/mole = 0.413636364 mole (calc. ans.)

≅ 0.414 mole (3 sig. figs.)

6 0
3 years ago
IS THIS A BALANCED EQUATION <br> MgCl2 + Na2O -- &gt; MgO + 2 NaCl
Dmitriy789 [7]
Yes, this is balanced. Each part of the substance (like Mg) has the same number on both sides.

Hope this helps you:)
8 0
3 years ago
Are your knees the elbows of your legs or are your elbows the knees of your
Nimfa-mama [501]

Answer:

hi

Explanation:

it is confusing lol

but i think that it is C.both

hope it helps

have a nice day

5 0
3 years ago
Read 2 more answers
In which of the following sets are the charges given correctly for all the
Ronch [10]

Answer:

B) K⁺, Sr²⁺ , O²⁻

Explanation:

Potassium is present in group one. It is alkali metal and have one valance electron.Potassium need to lose its one valance electron and form cation to get complete octet.

That's why it shows K⁺.

Sr is alkaline earth metal. It is present in group two. It has two valance electrons. Strontium needed to lose its two valance electrons and get stable electronic configuration.

When it loses its two valance electrons it shows cation with charge of +2.

Sr²⁺

Oxygen is present in group 16. It has sex valance electrons. It needed two more electrons to complete the octet. That's why oxygen gain two electron and form anion with a charge of -2.

O²⁻

3 0
3 years ago
If a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay, what will be the new element?
Charra [1.4K]

Answer:

The new element will be thorium-226 (²²⁶Th).

Explanation:

The beta decay is given by:

^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y + \beta^{-} + \bar{\nu_{e}}

Where:

A: is the mass number

Z: is the number of protons  

β⁻: is a beta particle = electron

\bar{\nu_{e}}: is an antineutrino

The neutral atom has 88 electrons, so:

e^{-} = 88 = Z

Hence the element is radium (Ra), it has A = 226.

If Ra undergoes 2 rounds of beta minus decay, we have:

^{226}_{88}Ra \rightarrow ^{226}_{89}Ac + \beta^{-} + \bar{\nu_{e}}    

^{226}_{89}Ac \rightarrow ^{226}_{90}Th + \beta^{-} + \bar{\nu_{e}}

Therefore, if a neutral atom with 88 electrons undergoes 2 rounds of beta minus decay the new element will be thorium-226 (²²⁶Th).

I hope it helps you!    

8 0
3 years ago
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