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vaieri [72.5K]
3 years ago
15

In the chromatography of the reaction mixture, water absorbed on cellulose functioned as the stationary phase. What was the prin

cipal factor determining the migration of individual components in the sample?
Chemistry
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

HYDROGEN BONDING (determines rate of migration)

Explanation:

There are two forces acting on the sample:

<u>Gravity/ Capillary action force:</u> This can include gravity, pumping of fluid through the tube, or the capillary action of the liquid when moving up the sheet of paper.

<u>Interactive force with the gel used:</u> The another force is dependent on the fundamental properties of individual components with fluid. These can be polarity, charge, adhesive nature, etc.

The most type of the chromatography is exploiting polarity of the molecules. So in TLC, we have a sheet coated with silica gel usually (polar), and a liquid that contains a mixture of different compounds which is being pushed up paper through the capillary action.  

Some liquid's polarity will be greater than the others, and that's why the liquids move at various speeds based on favorable/ unfavorable interactions between different compounds in the mixture.

In this way, one can separate a mixture into individual constituting parts.

<u>Thus, the relative amount of hydrogen bonding to the stationary phase will determine the Relative Rate of Migration of the various components in the sample.</u>

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ANSWER:
A. n=5 to n=1

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6 0
3 years ago
Which change to the experimental design would improve the reliability of the engineers' measurements?
luda_lava [24]

Answer:

c

Explanation:

sorry if im wrong my apolgies but i think c cus thats the only one that says equal amounts of something

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4 0
3 years ago
Which net ionic equation would match this description of a chemical reaction: When a
krok68 [10]

Answer:

3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)

Explanation:

Mg(NO_{3})_{2}, Na_{3}PO_{4} are strong electrolytes. Hence they are fully ionized in aqueous solution.

Mg_{3}(PO_{4})_{2} is a sparingly soluble salt. Hence it remains undissociated in aqueous solution.

So, total ionic equation:

3Mg^{2+}(aq.)+6NO_{3}^{-}(aq.)+6Na^{+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)+6Na^{+}(aq.)+6NO_{3}^{-}(aq.)

Net ionic equation is written by omitting spectator ions from total ionic equation.

Here, Na^{+} and NO_{3}^{-} ions are spectator ions as they remain present on both side of total ionic equation.

So, net ionic equation:

3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)

So, option (d) is correct.

6 0
3 years ago
How many atoms are in 2.00 moles of Helium
Snezhnost [94]

Answer:

maybe try 4.002602, good luck

7 0
3 years ago
The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
Dennis_Churaev [7]
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.

Hope it helps
6 0
3 years ago
Read 2 more answers
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