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antoniya [11.8K]
3 years ago
11

Add one or more curved arrows to show the movement of electrons in the reaction. To draw the arrows, select More in the drawing

menu, then select the appropriate curved arrow. Click on a bond or electron to start a curved arrow. Do not start from an atom. Use the select tool to move the arrow head and tail to the desired placement. When the curved arrow changes from red to black, your arrow has an appropriate starting and ending point. Draw curved arrows. Select Draw Rings More Erase С 0 heat -=-=- H3C—0. +.0—CH HCO CH, 2
Chemistry
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

H3C - O - O - CH -HCOCH2.

Explanation:

Before chemical reaction can occur, some steps has to be followed in order to give the final product (s), this steps can be shown by drawing the chemical compound and showing how bonds are being broken or formed. Showing this in a stepwise manner is known as reaction mechanism.

From the question above, it is given that the products after heating the reactant gives H3C—0. +.0—CH HCO CH2.

The starting material can be deduce as;

H3C - O - O - CH -HCOCH2.

Heat causes something to divide or melt. Kindly check the attached picture which shows how the deduced starting compound splits to give H3C—0. and .0—CH HCO CH2.

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Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

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V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

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