Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:


Z = 1.71
Z = 1.71 has a p-value of 0.9564.
1 - 0.9564 = 0.0436.
0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.
More can be learned about the normal distribution at brainly.com/question/24663213
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Answer:
3,869.72
Step-by-step explanation:
The number of ratios from students to adults would be a/s
15 i dont know what u mean hope i helped bye
10 rows= 12 mins
there's 25 rows in all so break it down into 10, 10, and 5 to make it more simple
12+12= 24 minutes for 20 rows
since you only have 5 rows left (which is half of ten), you divide the 12 by two as well.
12mins/2= 6 minutes for 5 rows
24mins+6mins= 30 minutes
answer: It will take 30 minutes to knit 25 rows