Use the distributive property to remove the parentheses.<br> 9(x-3)

Lisa is sitting on the dock beside the lake she drops a rock from her hand into the lake after the rock hits the surface of the

soldi70 [24.7K]

Answer: 4.2495 feets

Step-by-step explanation:

Given the following :

Rate of change (speed) when rock hits the lake surface = - 3in/s

Distance or depth after 5 seconds :

Distance = rate of change * time

Distance = (- 3 in/s × 5) = - 15 inches

1 inch = 0.0833 feet

15 inches = (-15 * 0.0833) = - 1.2495 feets

Distance between Lisa's hand and lake surface = 3 feets :

Distance between Lisa's hand and rock after 5 seconds :

(3 feets + 1.2495 feets) = 4.2495 feets

5 0

2 years ago

children's $30 per day plus $5 for every sale that she makes at her job on Thursday she wants to earn at least $60

professor190 [17]

Approximately 2 days to make at least 60 dollars.

3 0

3 years ago

Simplify<br> 8V 28<br><img src="https://tex.z-dn.net/?f=8%20%5Csqrt%7B28%7D%20" id="TexFormula1" title="8 \sqrt{28} " alt="8 \sq

omeli [17]

“42.3” I wish I got easy questions like you do

5 0

3 years ago

Whats 5(3× + 4) - 3 (-2× +11)

denpristay [2]

Answer:

21x+53

Step-by-step explanation:

8 0

3 years ago

The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

Use the distributive property to remove the parentheses. 9(x-3)