Answer:
a) Put x=10, then the both terms will be same.
b) (2x+3) and 23
c) (2x+3) is a general term for all values of x and 23 is a particular value for x=10
Step-by-step explanation:
a) Considering the following two fractions (4x²+8x+3)/(2x+1) and 483/21, they are equivalent to each other for the value of x =10.
Therefore, if you put x=10 in the fraction (4x²+8x+3)/(2x+1), then it will become 483/21. (Answer)
b) The quotient of the fraction (4x²+8x+3)/(2x+1) will be obtained by as follows:
(4x²+8x+3)/(2x+1) {By factorizing the numerator}
=(4x²+6x+2x+3)/(2x+1)
=(2x+3)(2x+1) / (2x+1)
=2x+3
Again, the quotient of the fraction 483/21 =23 (Answer)
c) Again, if you put the value of x =10 in the quotient (2x+3), then it will result 23. Therefore, (2x+3) is a general term which is valid for all the real values of x and 23 is a particular value for x=10. (Answer)
Answer:
Yes
Step-by-step explanation:
Line AB touches the circle at point B, but doesn't intersect through the circle.
Answer:
B
Step-by-step explanation:
For y to be a function of x, x must only have one value for each y value.
In B, the number 10 comes up twice in the x row. Therefore, y is not a function of x.
<span>12.5% of 64=8 Would be the answer to this.</span>
Answer:
The probability is 0.05 or 5%
Step-by-step explanation:
Of 6 cars the probability of 3 being a lemon is:
[tex]frac{{3!3!}{6!}} [\tex]
Picking the first one a lemon is [tex]frac{{3}{6}} [\tex] , the second one also lemon [tex]frac{{2}{5}} [\tex] and the third one [tex]frac{{1}{4}} [\tex].
[tex]frac{{3*2*1}{6*5*4}} [\tex] can be rearanged as
[tex]frac{{3!3!}{6!}} [\tex]
