A line has a slope of 6 and a y-intercept of 5. What is its equation in slope-intercept form?

Mathematics

1 answer:

kvasek [131]2 years ago

3 0

Answer:

The equation in slope-intercept form is y = 6x + 5

Step-by-step explanation:

The slope-intercept form of the linear equation is y = m x + b, where

m is the slope

b is the y-intercept

Let us solve the question

∵ A line has a slope of 6

∵ m is the slope of the line

∴ m = 6

∵ The line has a y-intercept of 5

∵ b is the y-intercept

∴ b = 5

→ Substitute the values of m and b in the slope-intercept form

∵ y = m x + b

∴ y = 6x + 5

∴ The equation in slope-intercept form is y = 6x + 5

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jenyasd209 [6]

Answer:

Step-by-step explanation:

x = last month

y = this month

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3 years ago

What is the amplitude, period, and phase shift of y= 5cos( x/2 + 2pi/3)

nordsb [41]

Y = A cos(Bx + C)
A - amplitude
$\frac{2\pi}{B}$ - period
$- \frac{C}{B}$ - phase shift

$y=5\cos{( \frac{x}{2} + \frac{2\pi}{3} )}
\\
\\y=5\cos{( \frac{1}{2}x + \frac{2\pi}{3})}
\\
\\A=5,B= \frac{1}{2},C= \frac{2\pi}{3}$

Amplitude: 5
Period: $\frac{2\pi}{B}=\frac{2\pi}{\frac{1}{2}}=4\pi$
Phase shift: $- \frac{C}{B} =- \frac{\frac{2\pi}{3}}{\frac{1}{2}}= -\frac{4\pi}{3}$