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3 years ago

7.5583 x 10^4 - 7.2301 x 10^4

Mathematics

1 answer:

Allisa [31]3 years ago

4 0

3237 is your answer.

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Solve the equation for all real solutions.<br> 8w2 + 2w + 2 = 3

fredd [130]

Answer:

Step-by-step explanation:

w= 1 /4 or w= −1/ 2

3 0

3 years ago

Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building materials and how the stren

Slav-nsk [51]

The logarithmic model for the length when the strength is of 8 Pascals is given by:

$f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3$
That is, the length is of 3 units.

<h3>What is the function?</h3>

The strength in Pascals for a building of length x is given by:

$f(x) = 2^x$

To find the length given the strength, we apply the inverse function, that is:

$2^y = x$

$\log_{2}{2^y} = \log_2{x}$

$y = \log_2{x}$

Hence, when the strength is of 8 Pascals, $x = 8$ , and the length is given by:

$f^{-1}(8) = \log_{2}{8} = \log_2{2^3} = 3$

You can learn more about logarithmic functions at brainly.com/question/25537936

6 0

2 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers

When adding or subtracting two decimals, what is the first thing you must do

polet [3.4K]

Line up the decimals

5 0

3 years ago

Help pleaseee :)!!!!!!!!!

harkovskaia [24]

Answer:

5x/x+3

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

3 0

3 years ago

Read 2 more answers