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2 years ago

15

PERSONALLY I thought it would be 98 Bc like yk..BUT I FEEL LIKE IM WRONGsend help beggin cryin throwin up I hate geometry so muc

h

1 answer:

Talja [164]2 years ago

6 0

Answer:

98

Step-by-step explanation:

It is 98! x and the 98 degree angle are corresponding angles and m is parallel to n. dw I hate geometry too.

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2 years ago

Find the value of the missing coefficient in the factored form of 8f^3-216g^3

adoni [48]

Answer:

The value of the missing coefficient is 12

Step-by-step explanation:

* Lets explain how to factorize the difference of two cubes

- The factorization of the difference of two cubes like a³ - b³, is a

product of a binomial and trinomial

- The binomial is the cube root of the first term and the second term

∵ The ∛a³ = a and ∛b³ = b

∴ The binomial is (a - b)

- We will find the trinomial from the binomial by square the 1st term

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binomial with opposite sign of the binomial and square the 2nd

term of the binomial

∴ The trinomial is (a² + ab + b²

∴ The factorization of (a³ - b³) is (a - b)(a² + ab + b²)

* Lets solve the problem

∵ 8f³ - 216g³ is the difference of two cubes

∵ ∛(8f³) = 2f

∵ ∛(216g³) = 6g

∴ The binomial is (2f - 6g)

- Lets make the trinomial

∵ (2f)² = 4f²

∵ (2f)(6g) = 12fg

∵ (6g)² = 36g²

∴ The trinomial = (4f² + 12fg + 36g²)

∴ The factorization of 8f³ - 216g³ = (2f - 6g)(4f² + 12fg + 36g²)

∴ The value of the missing coefficient is 12

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3 years ago

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Step-by-step explanation:

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Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = $^{52}C_8$

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = $^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1$ [since 1 suit has 13 cards]

The required probability = $=\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}$

$=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757$

Hence, the required probability is 0.003757 (approx).

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