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Artyom0805 [142]
3 years ago
13

X^2y^4/z^3 / x^3z^2/y

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer: y3/xz

Step by step is provided in the screenshot below

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I believe the answer is 2 if that’s an option
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The ratio of the length of the corresponding sides of two rectangles is 5:8. The area of the smaller rectangle is 130 m2. To the
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Read 2 more answers
Amy reached into a bag, recorded the color of the tile she picked, returned the tile and drew again. These are the tiles she has
Vedmedyk [2.9K]

Answer:

(a) P(next ball with blue) =  \frac{3}{10}       (b)  P(Not to be red) = 1-\frac{2}{5} =\frac{3}{5}

(c)  P(drawing 70 times yellow ball) = \frac{1}{10} \times 70 = 7.

Step-by-step explanation:

Given that,

The total outcomes of the color of tile are :-

Red , Red, Blue, Yellow, Blue, Red, Green, Red, Blue, Green.

From the Question,

Total number of outcomes = 10

(a) What is the probability that her next draw will be blue ?

        Red = 4,

        Blue = 3,

        Green = 2,

        Yellow = 1.

   P(next ball with blue) =  \frac{3}{10}.

(b) What is the probability that her next draw will NOT be red?

    P(Red ball) =  \frac{4}{10} = \frac{2}{5}

But we have to find

   P(Not to be red) = 1-\frac{2}{5} =\frac{3}{5}

(c) If Amy draws 70 more times with the same tiles from the question above, what probability would you expect a yellow?

  P(Yellow ball) =  \frac{1}{10}

drawing it 70 times we get the probability

   P(drawing 70 times yellow ball) = \frac{1}{10} \times 70 = 7.

5 0
3 years ago
The sum of the first 6 terms of a geometric series is 15,624 and the common ratio is 5.
nikitadnepr [17]

Answer:

  4

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The sum of n terms of a geometric series with first term a1 and common ratio r is given by ...

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Then we have ...

  1 = a1/4 . . . . . divide by 15624

  4 = a1 . . . . . . multiply by 4

The first term of the series is 4.

5 0
3 years ago
Graph both functions to find the solution(s) to the system.
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   <span> f(2) = 2×2 − 1 = 3</span>

The point of intersection is (2, 3).

The example shows that we can find the point of intersection in two ways.
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