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Artyom0805 [142]
3 years ago
13

X^2y^4/z^3 / x^3z^2/y

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer: y3/xz

Step by step is provided in the screenshot below

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Quick Math, Please Help! Thank you!
lesantik [10]

Answer:

The remaining side has a length of six units.

Step-by-step explanation:

We know that this is an Isosceles triangle because angles A and C are marked as being the same angle.  So we know that AB and CB are the same length.

As we're given their lengths, we can simply equate the two, and solve for x:

x + 4 = 3x - 8\\12 = 2x\\x = 6

So we know that the remaining side has a length of 6.

5 0
2 years ago
Read 2 more answers
Anna, Boris, and Clara thought of 1 number each Ana's number increased by 20 is 21 greater than boris's number decreased by 22.
sleet_krkn [62]

Answer:

Clara's number is 42 less than Anna's number

Step-by-step explanation:

We can start this problem out by setting our variables up:

A= Anna's number

B= Boris's number

C= Clara's number

so we can use them to build our equations. We can sepparate the problem into little more understandable pieces of information, let's start with the first piece of information:

- "Ana's number increased by 20"

A+20

- "boris's number decreased by 22"

B-22

- "21 greater than boris's number decreased by 22."

(B-22)+21

- "Ana's number increased by 20 is 21 greater than boris's number decreased by 22."

A+20=(B-22)+21

This is our first important equation here. Let's go with the second part of the problem:

- "Boris's number decreased by 20"

B-20

- "claras number increased by 22"

C+22

- "21 greater than claras number increased by 22"

(C+22)+21

Now the whole thing:

"Boris's number decreased by 20 is 21 greater than claras number increased by 22."

B-20=(C+22)+21

This is our second important equation.

So now we have the following system of equations:

A+20=(B-22)+21

B-20=(C+22)+21

We can now simplify the equations by combining like terms so we get:

Equation 1:

A+20=(B-22)+21

we can get rid of the parenthesis so we get:

A+20=B-22+21

We can subtract a 20 from both sides of the equation so we get:

A=B-22+21-20

We perform the subtractions so we get:

A=B-21

Equation 2:

B-20=(C+22)+21

We get rid of the parenthesis:

B-20=C+22+21

We add a 20 to both sides so we get:

B=C+22+21+20

We can now perform the additions so we get:

B=C+63

And now we can combine the equations. In this case we can substitute equation 2 into equation 1 to get:

A=C+63-21

We combine like terms to get:

A=C+42

We can subtract 42 from both sides to get:

C=A-42

which reads:

Clara's number is 42 less than Anna's number.

3 0
3 years ago
Which method is the best method for solving the equation?<br> <img src="https://tex.z-dn.net/?f=8x%5E%7B2%7D%20-%2013x%20%2B%203
Paladinen [302]

Answer:

Step-by-step explanation:

Which Method Should Be Used to Solve a Quadratic Equation? Quadratic equations are of the form ax2 + bx + c = 0 where a, b and c are real numbers, a ≠ 0. Quadratic equations have two solutions, but it is possible that one solution may repeat. happy to help

3 0
3 years ago
A publisher needs to send many books to a local book retailer and will send the books in a combination of small and large boxes.
Paladinen [302]

Answer:

Answer:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

Where xx is the number of small boxes sent and yy is the number of large boxes sent.

Step-by-step explanation:

Let be xx the number of small boxes sent and yy the number of large boxes sent.

Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:

20x+30y=28020x+30y=280

According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

y=4xy=4x

Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:

\{ {{20x+30y=280} \atop {y=4x}} .{

y=4x

20x+30y=280

.

7 0
3 years ago
Please give an explanation thank youuu<br> Write √216 as a power of 6
Nesterboy [21]

Answer:

solution

here,

<h3>the power of route 216 of 6 is 6to the power 3</h3>
3 0
2 years ago
Read 2 more answers
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