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Ahat [919]
3 years ago
15

Once a woman is cured of the human papilloma virus, she does not have to worry about future effects. Please select the best answ

er from the choices provided. T F
Mathematics
2 answers:
MatroZZZ [7]3 years ago
5 0
The Answer To This Is False
Anytime Somebody Is Cured Of A Disease They Always Have To Worry About It Coming Back Because It Has Been In Their Body Already
Hope This Helps

lara [203]3 years ago
3 0
True, because her body will have become immune to the virus.

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Answer this please tell me if I’m correct
jek_recluse [69]
Yes you are correct, :)
6 0
3 years ago
What is the lowest term of 75/60 as an improper fraction?
Katena32 [7]
75/60 = 15/12 = 5/4. This is the lowest term
5 0
3 years ago
Read 2 more answers
7-8x+4y+18-3x-y simplify​
Katyanochek1 [597]

Answer:

-11x +3y + 25

Step-by-step explanation:

7-8x+4y+18-3x-y

= -8x-3x +4y-y +18+7 (putting like terms together)

= -11x +3y + 25 (Adding like terms)

7 0
3 years ago
Round 877.71 to the nearest tenth
Rainbow [258]
The 7 after the decimal is in the tenths place, so look at the one in the hundredths place. It is less than 5, so the 7 is not rounded up and stays 7. 877.7 is 877.71 rounded to the nearest tenth.
4 0
4 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
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