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2 years ago

8

A middle school is selling candy bars to raise money for new calculators. The graph shows the number of candy bars sold, x, and

the amount of money collected, y.
Enter a value that completes the equation correctly.

Y=__x

2 answers:

Aliun [14]2 years ago

6 0

Y equals 2.5x because it increases 2.5

Naily [24]2 years ago

4 0

Y=2.5x as each time it increases by 2.5

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A micro-photograph of a human hair shows the hair magnified 150 times. If the hair is

stepan [7]

Answer:

<em>The actual width of the hair is 20 / 150 = 0.13 mm</em>

Step-by-step explanation:

<u>Scaling</u>

Objects can be represented in a reduced or augmented size by using scaling which is basically multiplying or dividing by a constant factor. We use scaling in several applications of real-life.

The human hair is magnified 150 times by a micro-phtograph. This is the scale factor.

The hair can be seen 2 cm wide in the photograph.

Converting to millimeters, 2 cm = 2*10 = 20 millimeters.

The actual width of the hair is 20 / 150 = 0.13 mm

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2 years ago

Plz help will be marked BRAINLIEST <br> Thanks !

zloy xaker [14]

Answer:

The first two

Step-by-step explanation:

Do the parenthesis of the first and you will get the original equation.

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3 years ago

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Help i can’t find this answer anywhere.

murzikaleks [220]

Answer:

B, I think that's the answer

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3 years ago

Vertex: <br> (<br> 2<br> ,<br> 0<br> )<br> , Passes through: <br> (<br> 5<br> ,<br> −<br> 18<br> )

NemiM [27]

Answer:

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Step-by-step explanation:

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2 years ago

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

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3 years ago