I think that the sum will always be a rational number
let's prove that
<span>any rational number can be represented as a/b where a and b are integers and b≠0
</span>and an integer is the counting numbers plus their negatives and 0
so like -4,-3,-2,-1,0,1,2,3,4....
<span>so, 2 rational numbers can be represented as
</span>a/b and c/d (where a,b,c,d are all integers and b≠0 and d≠0)
their sum is
a/b+c/d=
ad/bd+bc/bd=
(ad+bc)/bd
1. the numerator and denominator will be integers
2. that the denominator does not equal 0
alright
1.
we started with that they are all integers
ab+bc=?
if we multiply any 2 integers, we get an integer
<span>like 3*4=12 or -3*4=-12 or -3*-4=12, etc.
</span>even 0*4=0, that's an integer
the sum of any 2 integers is an integer
like 4+3=7, 3+(-4)=-1, 3+0=3, etc.
so we have established that the numerator is an integer
now the denominator
that is just a product of 2 integers so it is an integer
<span>2. we originally defined that b≠0 and d≠0 so we're good
</span>therefore, the sum of any 2 rational numbers will always be a rational number <span>is the correct answer.</span>
Answer:
1/2= 5/10
5/10 - 3/10 = 2/10 or 1/5
so planet X is 1/5 of a light-year closer
Step-by-step explanation:
Option C: There are no solutions
Explanation:
The linear equations is graphed.
We need to determine the solution of the system of equations.
The solution of the equations can be determined by finding the point of intersection of the two equations.
From the figure, it is obvious that the two equations are parallel to each other.
Also, the parallel lines have the same slope and the parallel lines never intersect.
Hence, the system consisting of parallel lines have no solution.
Therefore, the solution to the system of linear equations graphed is no solution.
Thus, Option C is the correct answer.
Answer:
hope this helps you...
Step-by-step explanation:
please mark this as brainliest
Answer:
No.
Step-by-step explanation:
There are two different ways to do this - solve for x in the given equation or substitute the value for x and see if you get a true statement.
3x + 7 = 13 subtract 7 from both sides
3x = 6 divide by 3 on both sides
x = 2
3(3) + 7 = 13
9 + 7 = 13
16 ≠ 13
Therefore, x = 3 is not a solution for 3x + 7 = 13.
