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This question asks for a line that passes through the point P(<span>– 3, 0</span>), whose slope is m = <span>– 2.
The equation of this line is
I hope this helps. =)
Tags: <em>point slope intersect line equation analytical geometry linear algebra</em>
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Answer: The answer is 1296
<span><span>b=<span><span>703w</span><span>h2</span></span></span><span>b=<span><span>703w</span><span>h2</span></span></span></span>Since <span>ww</span> is on the right side of the equation, switch the sides so it is on the left side of the equation.<span><span><span><span>703w</span><span>h2</span></span>=b</span><span><span><span>703w</span><span>h2</span></span>=b</span></span>Solve for <span>ww</span>.Tap for fewer steps...Multiply both sides of the equation by <span><span>h2</span><span>h2</span></span>.<span><span>703w=b⋅<span>(<span>h2</span>)</span></span><span>703w=b⋅<span>(<span>h2</span>)</span></span></span>Simplify the right side.Tap for more steps...<span><span>703w=b<span>h2</span></span><span>703w=b<span>h2
</span></span></span>Divide each term by <span>703703</span> and simplify.<span>w=<span><span><span>b<span>h2</span></span>703</span></span></span>
I think the answer is 80 pounds
Distance1 ÷ (Jaime's velocity + wind velocity) =
Distance2 ÷ (<span>Jaime's velocity - wind velocity)</span>
57 / (Jaime's velocity + 4) = 33 / (<span>Jaime's velocity -4)
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57 / 33 = (Jaime's velocity + 4) / (Jaime's velocity - 4)
(57 * -4) +57 * (Jaime's velocity) = (33 * 4) +33 * (Jaime's velocity)
-228 + 57 JV = 132 + 33 JV
24 JV = 360
Jaime's velocity = 15
Source
http://www.1728.org/veloccal.htm
(see Problem E)