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Katen [24]
3 years ago
11

Someone help me please it’s for at 11:59pm

Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

11 sqrt 2

Step-by-step explanation:

it's a 45 45 90 triangle

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One root of f(x)=x^3+10x^2-25-250 is x = –10. What are all the roots of the function? Use the Remainder Theorem. x = –25 or x =
Alex_Xolod [135]

Answer:

All zeros are

x=-10 , x=-5 , x=5

Step-by-step explanation:

we are given function as

f(x)=x^3+10x^2-25x-250

we are given one of zero is x=-10

we have to use Remainder theorem

we can find all possible factor of 250

250=-5\times 5\times -10

so, we will check zeros at x=-5 and x=5

At x=-5:

we can plug x=-5

f(-5)=(-5)^3+10(-5)^2-25(-5)-250

f(-5)=-125+250-\left(-125\right)-250

f(-5)=0

At x=5:

we can plug x=5

f(5)=(5)^3+10(5)^2-25(5)-250

f(5)=125+250-\left(125\right)-250

f(5)=0

So, other zeros are

x=-5 and x=5

All zeros are

x=-10 , x=-5 , x=5

6 0
3 years ago
Read 2 more answers
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