Find the probability that a randomly selected point within the circle falls in the white area
1 answer:
Answer:
Step-by-step explanation:
The white area is the area of the circle minus the area of the triangle.
Aw=pr^2-hb/2
Aw=p4^2-6.5(6)/2
Aw=16p-19.5
The probability of selecting the white area is the white area divided by the area of the circle
P(W)=(16p-19.5)/(16p), p=3.14
P(W)=0.61
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