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jonny [76]
3 years ago
7

Find the probability that a randomly selected point within the circle falls in the white area

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

Step-by-step explanation:

The white area is the area of the circle minus the area of the triangle.

Aw=pr^2-hb/2

Aw=p4^2-6.5(6)/2

Aw=16p-19.5

The probability of selecting the white area is the white area divided by the area of the circle

P(W)=(16p-19.5)/(16p), p=3.14

P(W)=0.61

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Answer:

Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively? 204.

Step-by-step explanation:

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

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The pattern of the normalized differential equation can be represented as:

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This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

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From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

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\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

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Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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Steps in Dividing fractions.

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Step 2. Multiply the 1st fraction to the reciprocal of the 2nd fraction. Follow steps in multiplying fractions.

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3 years ago
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3 years ago
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6 0
3 years ago
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