Slope = (-3+4)/(0+5) = 1/5
passing (-2,2)
y = mx +b
2 = 1/5(-2) + b
2 = -2/5 + b
so b = 2 +2/5 = 12/5
equation
y = 1/5x + 12/5
answer is B y = 1/5x + 12/5
Answer:
12r/t
Step-by-step explanation:
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!