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1 year ago

Explain the difference between using area and volume with 2-D and 3-D figures.

1 answer:

6 0

The difference between Area and Volume lies in the fact that the former relates to plane shapes while the latter takes the concept of solid shapes into account.

<h3>What is the difference between Area and Volume?</h3>

The distinctive characteristic of area is the space occupied by a two-dimensional, 2D flat object in a plane while Volume on the other hand is defined as the space covered by a three-dimensional, solid object. The area is quantised in square units while the volume is quantised in cubic units.

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A baseball player gets 7 hits in the first 15 games of the season. if he continues hitting at the same rate, how many hits will

inessss [21]

Hey there,
15 games = 7 hits
1 game = 7 / 15
= <span>0.46666666666
45 games = </span><span>0.46666666666 x 45
= 21

Hope this helps :))

<em>~Top♥</em>
</span>

3 0

2 years ago

1.13 Thank you! (Sorry it’s so blurry)

VikaD [51]

$\sqrt[8]{48^4}$ can be rewritten as $48^4$ to the $\frac{1}{8}$ power:

$(48^4)^ \frac{1}{8}$

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

$(48^ \frac{1}{2})$

This is equivalent to $\sqrt{48}$ , so now, we just simplify:

$\sqrt{48}= \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}$

So:

$\sqrt[8]{48^4} =4 \sqrt{3}$

4 0

3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

2 years ago

Selma is about to purchase a new television that is listed for $415.99. If sales tax is 7.75%, what

Alex787 [66]

Answer:

448.23

Step-by-step explanation:

Sales tax is addition to the original price

The original price is 100%

First we find 1% of this, which is 415.99 / 100 = 4.1599

Then multiply this by 7.75 = 32.239225

Add this to the original price = 415.99 + 32.239225 = 448.229225

You have to round this to an appropriate number as the question uses two decimal places I think this will suffice = 448.23

6 0

2 years ago

-6p + 30 = 12 please explain this problem please thankyou.

goblinko [34]

The answer is p=3, here is the process and the steps to find the answer.

7 0

2 years ago