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Likurg_2 [28]
3 years ago
10

Find the integral of arccos x /sqrt (1-x^2)dx.

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
The problem ask to find the integral of the trigonometric equation of arcos x/qrt(1-x^2)dx and the best answer that i could give base on the given equation and my further computation and that is <span>∫arccos(x)/sqrt(<span><span>1−<span>x2</span></span></span>dx)=1/2(arccos(x)<span>)2</span>+c. I hope are satisfied with my answer and feel free to ask for more </span>
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Answer:

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Step-by-step explanation:

We can write the following system of equations:

\begin{cases}x+y=6\\x-y=16\\\end{cases}

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2x=22,\: x=11

Plugging x=11 in any of the equations, we can solve for y:

11+y=6,\: y=-5

Verify that the solution pair (11, -5) works \checkmark

Therefore, the two numbers are \fbox{$-5\:\mathrm{and}\: 11$}.

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