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Likurg_2 [28]
3 years ago
10

Find the integral of arccos x /sqrt (1-x^2)dx.

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
The problem ask to find the integral of the trigonometric equation of arcos x/qrt(1-x^2)dx and the best answer that i could give base on the given equation and my further computation and that is <span>∫arccos(x)/sqrt(<span><span>1−<span>x2</span></span></span>dx)=1/2(arccos(x)<span>)2</span>+c. I hope are satisfied with my answer and feel free to ask for more </span>
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umka21 [38]
It’s P.E.M.D.A.S

P= parenthesis ()
E= exponent
M= multiplication or Multiply
D= Division or divided
A= Addition
S= Subtraction
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


4 0
3 years ago
Can someone hello son please make sure it’s right :)
Sedaia [141]

Answer: x= -12

Step-by-step explanation:

These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12

4 0
2 years ago
Read 2 more answers
Use quadratic regression to find
Rashid [163]

The quadratic equation is given by:

y = 3x² + 10x - 8

The standard equation of a parabola is given by:

y = ax² + bx + c

Where a, b, c are constants

At point (4, 80):

80 = a(4)² + b(4) + c

16a + 4b + c = 80     (1)

At point (-3, -11):

-11 = a(-3)² + b(-3) + c

9a - 3b + c = -11     (2)

At point (-1, -15):

-15 = a(-1)² + b(-1) + c

a - b + c = -15     (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = 3, b = 10, c = -8

Therefore the quadratic equation becomes:

y = 3x² + 10x - 8

Find out more on quadratic equation at: brainly.com/question/1214333

8 0
2 years ago
15 points, no messing around, please do it right
cupoosta [38]

Answer:

416 is your answer!!!

Step-by-step explanation:

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8 0
2 years ago
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grandymaker [24]
(X1=1, y1=7) and (x2= -4, y2 =-8)

Slope = ( y2-y1)/(x2-x1)= (-8-7)/(-4-1)= -15/-5=3

Slope is 3
5 0
3 years ago
Read 2 more answers
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