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Likurg_2 [28]
3 years ago
10

Find the integral of arccos x /sqrt (1-x^2)dx.

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0
The problem ask to find the integral of the trigonometric equation of arcos x/qrt(1-x^2)dx and the best answer that i could give base on the given equation and my further computation and that is <span>∫arccos(x)/sqrt(<span><span>1−<span>x2</span></span></span>dx)=1/2(arccos(x)<span>)2</span>+c. I hope are satisfied with my answer and feel free to ask for more </span>
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A rectangular pool is 10 meters wide and 16 meters long.What is the area of the pool? What is asked?What are given?What is/are t
Morgarella [4.7K]
<h3>Answer:</h3>

A=160 m

<h3>Solution:</h3>
  • The formula for the Area of a rectangle is:
  • A=LW
  • In the above formula, L stands for the length and W stands for the width.
  • We are given:
  • L=16 m
  • W=10 m
  • We are asked to find the area of the rectangular pool.
  • The operation that we're going to use here is:
  • Multiplication.
  • Multiply:
  • A=16*10
  • A=160 m

Hope it helps.

Do comment if you have any query.

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2 years ago
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Answer:the first one can you pick more?

Step-by-step explanation:

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3 years ago
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noname [10]

Answer:

She can invite 109 guests and be right on top of budget. If she wants to spend less than her budget though she can only invite 108 people.

Step-by-step explanation:

First you have to subtract 5,748 - 2,478 which is 3270. Next you have to divide 3270 by 30 because each person costs 30 dollars. 3270 divided by 30 is 109.

I hope this helps! Please mark me brainliest if I am correct! Have a nice day!

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Answer:

Brainless bruv I gonna say that's a insult but ok

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