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Ipatiy [6.2K]
3 years ago
9

Help? Please. I really need help

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Any other product in Quadrant IV will be negative also, so Quadrant IV is part of my answer. The points (x, y), with xy < 0, lie in Quadrants II and IV.

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Help me with this please!!!!!!!
natta225 [31]

Answer:

The answer is 8.54

6 0
2 years ago
The figure shows a barn that mr fowler is building for his fame
sdas [7]
Where is the figure KingBroski?
3 0
3 years ago
A rectangle has a height of t^2+7t+6t
jek_recluse [69]

Answer:

2t^3+15t^2+19t+6

Step-by-step explanation:

Height of the Rectangle=t^2+7t+6

Width of the Rectangle=2t+1

Area of the Rectangle = Height X Width

=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\

The area of the rectangle is 2t^3+15t^2+19t+6

4 0
3 years ago
Identify the number of solutions or zeros<br><br> 2x^2+5x-9=0
Anon25 [30]
There are going to be two solutions because the "biggest" x is x^2 but you can factor to find what they actually are.

6 0
3 years ago
What is the distance between the two points shown?
bonufazy [111]
The distance is (-4, 4)

Explanation: I moved down 4 cubes (negative) and moved right 4 cubes (positive).

I hope I am right :)
7 0
2 years ago
Read 2 more answers
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