3 years ago

2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(g)

Chemistry

1 answer:

a_sh-v [17]3 years ago

7 0

Answer:

Not approved but I think 4(-393.5)+ 2(-241.8)) – (2(227) + 5(0))

The enthalpy change is -2511.6.

Explanation:

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The chemical equilibrium is given:

Kryger [21]

The volume of NO₂=6.25 L

<h3>Further explanation</h3>

Avogadro's stated :

<em>In the same T,P and V, the gas contains the same number of molecules </em>

So the ratio of gas volume = the ratio of gas moles

$\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}$

the volume of each gas (in a container of volume 10L) :

Total mol=10+10+20=40 mol

NO :

$\tt \dfrac{10}{40}\times 10=2.5~L$

O₂ :

$\tt \dfrac{10}{40}\times 10=2.5~L$

NO₂ :

$\tt \dfrac{20}{40}\times 10=5~L$

NO₂ (has increased by 25%) :

$\tt 0.25\times 5~L=1.25\\\\new~volume=5+1.25=6.25$

O₂ :

$\tt \dfrac{10}{20}\times 6.25=3.125$

NO :

$\tt \dfrac{10}{20}\times 6.25=3.125$

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