Question

The chemical equilibrium is given:

Answer 1

The volume of NO₂=6.25 L

Further explanation

Avogadro's stated :

In the same T,P and V, the gas contains the same number of molecules  

So the ratio of gas volume = the ratio of gas moles  

$\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}$

the volume of each gas (in a container of volume 10L) :

Total mol=10+10+20=40 mol

• NO :

$\tt \dfrac{10}{40}\times 10=2.5~L$

• O₂ :

$\tt \dfrac{10}{40}\times 10=2.5~L$

• NO₂ :

$\tt \dfrac{20}{40}\times 10=5~L$

NO₂ (has increased by 25%) :

$\tt 0.25\times 5~L=1.25\\\\new~volume=5+1.25=6.25$

• O₂ :

$\tt \dfrac{10}{20}\times 6.25=3.125$

• NO :

$\tt \dfrac{10}{20}\times 6.25=3.125$