Im going with c hope this helps
Living: biotic
Non-loving: abiotic
<span>2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
2 moles CH3OH ---------------- 3 moles O2
1.33 moles CH3OH ----------- ( moles O2)
moles O2 = 1.33 x 3 / 2
moles O2 = 3.99 / 2
= 1.995 moles of O2</span>
When sodium hydroxide (NaOH) is added to benzoic acid (C
), sodium benzoate and water (
) are formed because benzoic acid is weak acid and NaOH is strong base. The reaction is shown in diagram 1. To the tube of sodium benzoate, if 6 m HCl is added, sodium benzoate salt will react with HCl and produce benzoic acid and sodium chloride, NaCl. The reaction is shown in diagram 2.
.36 g of caffeine for this problem. 2% of 18g is 0.36g
