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Yuliya22 [10]
3 years ago
6

You need to cover the playground of a child development center with mulch. The playground is 125 feet long and 60 feet wide. You

want the mulch to be at least 6 inches deep.
How many cubic yards of mulch should you have delivered? Round your answer to the nearest whole number.
Mathematics
1 answer:
alexira [117]3 years ago
6 0
Volume of this child development center=long x width x deep.
we expressed all magnitudes (long, width and deep) in yards.
Data:
long=125 ft=125 ft * (1/3 yd/ft)=125/3 yd
width=60 ft=60 ft * (1/3 yd/ft)=20 yd
deep=6 in * (1 yd / 36 in)=1/6 yd

We calculate the volume:
volume=(125/3 yd)*(20 yd)*(1/6 yd)=138.8888....yd³≈139 yd³

Answer: 139 yd³
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-3 (x + 10) <br><br> HELP<br> PLEASE
galben [10]

Answer:

−3X−30

Step-by-step explanation:

5 0
3 years ago
Do you know how to do this question
Sever21 [200]

Percentage of the area shaded = 55%

Solution:

Perimeter of the square = 40 cm

Each side of the square = \frac{40}{4} = 10 cm

Area of the square = \text{side}^2

                               = 10²

                               = 100

Total area of the square = 100 cm²

The unshaded portion is two triangles.

Base of the smaller triangle = 10 cm – 7 cm = 3 cm

Height of the smaller triangle = 10 cm

Area of the smaller triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 3\times 10

Area of the smaller triangle = 15 cm²

Base of the larger triangle = 10 cm – 4 cm = 6 cm

Height of the larger triangle = 10 cm

Area of the larger triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 6\times 10

Area of the larger triangle = 30 cm²

Area of the shaded portion = Area of the square – Area of the smaller

                                                   triangle – Area of the larger triangle

                                              = 100 cm² – 15 cm² – 30 cm²

Area of the shaded portion = 55 cm²

Percentage of the area shaded = \frac{\text{Area of the shaded portion}}{\text{Total area of the square}}\times100\%

                                                    $=\frac{55}{100}\times100\%

Percentage of the area shaded = 55%

8 0
4 years ago
Functions f(x) and g(x) are described as follows: f(x) = −5x2 + 9 x g(x) 0 0 1 4 2 8 3 4 4 0 Which statement best compares the m
MArishka [77]

Which statement best compares the maximum value of the two functions?

A. It is equal for both functions

B. It is 3 units higher for f(x) than g(x)

C. It is 3 units lower for f(x) than g(x)

D. It is 1 unit higher for f(x) than g(x)

Solution : D. It is 1 unit higher for f(x) than g(x)

Given:

f(x) = −5x^2 + 9

g(x) is 0 0 1 4 2 8 3 4 4 0

We make a table for f(x) as well. We use same x vales given in g(x)

We plug in x values and find f(x)

x -----> g(x) ----> f(x)

0 -----> 0 ---->9

1 -----> 4 ----> 4

2 -----> 8 ---->-11

3 -----> 4 ---->-36

4 -----> 0 ----> -71

From the table we can see that maximum value of g(x) is 8 and maximum value of f(x) is 9 that is 1 unit higher for f(x) than g(x)

Answer is option D.

3 0
4 years ago
Why is “3 meals a day” a unit rate? It compares 1 meal to 1 day. It compares 1 meal to 3 days. It compares 3 meals to 1 day. It
asambeis [7]

Answer:

  It compares 3 meals to 1 day.

Step-by-step explanation:

"Unit rate" refers to a rate that has 1 unit in the denominator.

  (3 meals)/(1 day) . . . . "three meals per day"

has one unit (1 day) in the denominator, so that is a unit rate.

3 0
3 years ago
What is the value of E?
kozerog [31]
Hello!

∠E and the angle measuring 119 degrees (we'll refer to this as ∠A) can be classified as supplementary angles. Supplementary angles are two angles whose measures add to a sum of 180 degrees (a straight line). Therefore, we can conclude that sum of ∠E and ∠A is 180 degrees. We can use this information to create the following equation:

∠E + 119 = 180

Now subtract 119 from both sides of the equation:

∠E = 61

We have now proven that ∠E is equal to 61 degrees.

I hope this helps!
8 0
4 years ago
Read 2 more answers
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