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creativ13 [48]
3 years ago
9

Vertical asymptote of the function f(x)= x+2/x^2-3x-4

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

x = 4, -1

Step-by-step explanation:

You first have to find the value of x where the denominator is equal to 0 because this is where the function will become undefined:

x^{2} - 3x - 4 = 0

Now, to factor by grouping, find 2 numbers which add to -3 and multiply to -4:

1 and -4

Then, factor by grouping:

(x + 1)(x - 4) = 0

Next, solve for the values of x:

(x + 1) = 0

x = -1

(x - 4) = 0

x = 4

Finally, this means that the function has a vertical asymptote of x = 4 and x = -1

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<h3></h3><h3>Which statement is true?</h3>

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