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creativ13 [48]
3 years ago
9

Vertical asymptote of the function f(x)= x+2/x^2-3x-4

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

x = 4, -1

Step-by-step explanation:

You first have to find the value of x where the denominator is equal to 0 because this is where the function will become undefined:

x^{2} - 3x - 4 = 0

Now, to factor by grouping, find 2 numbers which add to -3 and multiply to -4:

1 and -4

Then, factor by grouping:

(x + 1)(x - 4) = 0

Next, solve for the values of x:

(x + 1) = 0

x = -1

(x - 4) = 0

x = 4

Finally, this means that the function has a vertical asymptote of x = 4 and x = -1

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Simplify the following expression using the distributive property: -8(2x - 5)
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Answer:

(B)-16+40

Step-by-step explanation: -8(2x-5)

-8*2=-16

-8*-5=40(positive because a negative multiplied by a negative is postive)

add the x to the answers...Then its -16x+40

Hope This Helps:)

5 0
3 years ago
1. Solve the system by graphing. Be sure to check your solution.<br> y=-x+3<br> y=x+1
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6 0
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Solve. -4 is greater than -4/3s <br><br> −4 &gt; − 4/3 s
alekssr [168]

Answer:

s>3

Step-by-step explanation:

Step 1: Flip the equation.

-4/3s <-4

Step 2: Multiply both sides by 3/(-4).

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s > 3

7 0
3 years ago
Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line
mylen [45]
A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t 
yr = 2 + 2 t 
zr = 6 + 2 t 

To represent the black ant, 
xb = t/2 
yb = 2 + 3 t 
zb = 2 + t 

To calculate,
at t = 0 
xb - xr = -3 
yb - yr - 2-2 = 0 
zb - zr = 2-6 = -4 
Therefore,
d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2 

If t = 2,
2 + 2*2 = 2 + 3*2
4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Match the systems of equations with their solutions.
Oksanka [162]

Answer:

See explanation for matching pairs

Step-by-step explanation:

Equations

(1)

x - y = 25

2x + 3y = 180  

(2)

2x - 3y = -5

11x + y = 550  

(3)

x - y = 19

-12x + y = 168

Solutions

(-17,-36)

(47, 33)

(51, 26)

Required

Match equations with solutions

(1) x - y = 25 and 2x + 3y = 180

Make x the subject in: x - y = 25

x = 25 + y

Substitute x = 25 + y in 2x + 3y = 180

2(25 + y) + 3y = 180

50 + 2y + 3y = 180

50 + 5y = 180

Collect like terms

5y = 180-50

5y = 130

Solve for y

y =26

Recall that: x = 25 + y

x = 25 + 26

x = 51

So:

(x,y) = (51,26)

(2)  2x - 3y = -5 and 11x + y = 550

Make y the subject in 11x + y = 550

y = 550 - 11x

Substitute y = 550 - 11x in 2x - 3y = -5

2x - 3(550 - 11x) = -5

2x - 1650 + 33x = -5

Collect like terms

2x  + 33x = -5+1650

35x = 1645

Solve for x

x = 47

Solve for y in y = 550 - 11x

y = 550 - 11 * 47

y = 550 - 517

y = 33

So:

(x,y) = (47,33)

(3)

x - y = 19  and -12x + y = 168

Make y the subject in -12x + y = 168

y = 168 + 12x

Substitute y = 168 + 12x in x - y = 19

x - 168 - 12x = 19

Collect like terms

x -12x = 168 + 19

-11x = 187

Solve for x

x = -17

Solve for y in y = 168 + 12x

y =168-12 *17

y =-36

So:

(x,y) = (-17,-36)

4 0
2 years ago
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