Question

Consider the function f(x)=6sin(x-pi/8)+8. What transformation results in g(x)=6sin(x-7pi/16)+1?​

Answer 1

Answer: we have a vertical shift of 7 units down, and a horizontal shift of 5*pi/16 units to the right.

Step-by-step explanation:

First, let's define the transformations:

Vertical shift.

If we have a function f(x), a vertical shift of N units is written as:

g(x) = f(x) + N

This will move the graph of f(x) up or down a distance of N units.

if N is positive, then the shift is upwards

if N is negative, then the shift is downwards.

Horizontal shift.

If we have a function f(x), a horizontal shift of N units is written as:

g(x) = f(x + N)

This will move the graph of f(x) to the right or left a distance of N units.

if N is positive, then the shift is to the left

if N is negative, then the shift is to the right.

Here we have:

f(x) = 6*sin(x - pi/8) + 8

and the transformed function:

g(x) = 6*sin(x - (7/16)*pi) + 1

We can assume that the transformations are a vertical shift of A units, and an horizontal shift of B units, then we can write:

g(x) = f(x + B) + A

g(x) = 6*sin(x + B - pi/8) + (8 + A) = 6*sin(x - (7/16)*pi) + 1

Then we must have that:

(x + B - pi/8) = x -  (7/16)*pi

B - pi/8 = -(7/16)*pi

B = -(7/16)*pi + pi/8 =  -(7/16)*pi +2*pi/16 = (-7 + 2)*pi/16 = -5*pi/16

And we also must have that:

8 + A  = 1

A = 1 - 8 = -7

Then the transformation is:

g(x) = f(x - 5*pi/16) - 7

This means that we have a vertical shift of 7 units down, and a horizontal shift of 5*pi/16 units to the right.