Answer:
9.36x + 0.66
Step-by-step explanation:
5.96x - 8.44 + 3.4x + 9.1 =
5.96x + 3.4x + 0.66 =
9.36x + 0.66
Answer:
log_a(b) - log_a(c) = log_a(\frac{b}{c})
Using that formula we get:
log_6(60) - log_6(30) = log_6(2)
Answer:
f(x) = 4x^2 + 2x - 4.
Step-by-step explanation:
Let the quadratic function be y = f(x) = ax^2 + bx + c.
For the point (-2, 8) ( x = -2 when y = 8) we have:
a(-2)^2 + (-2)b + c = 8
4a - 2b + c = 8 For (0, -4) we have:
0 + 0 + c = -4 so c = -4. For (4, 68) we have:
16a + 4b + c = 68
So we have 2 systems of equations in a and b ( plugging in c = -4):
4a - 2b - 4 = 8
16a + 4b - 4 = 68
4a - 2b = 12
16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:
8a - 4b = 24
Adding the last 2 equations:
24a = 96
a = 4
Now plugging a = 4 and c = -4 in the first equation:
4(4) - 2b - 4 = 8
-2b = 8 - 16 + 4 = -4
b = 2.
Answer:
x = 2
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(4+(4•(x-2)))-(2•(x+1)-x) = 0
Step 2 :
Equation at the end of step 2 :
(4 + 4 • (x - 2)) - (x + 2) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Equation at the end of step 4 :
3 • (x - 2) = 0
Step 5 :
Equations which are never true :
5.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : x-2 = 0
Add 2 to both sides of the equation :
x = 2
One solution was found :
x = 2
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