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2 years ago

6

Ruben is buying bricks for a project. He knows that 5 bricks weigh 26 1/4 lb. He wants to know the weight of 24 bricks. What is

the weight per brick?

2 answers:

Hatshy [7]2 years ago

8 0

Answer:

5.25 and for the second part 126

Step-by-step explanation:

trust

makkiz [27]2 years ago

4 0

Answer:

5.25 for each brick and 24 bricks is 126

Step-by-step explanation:

You find this by dividing 26.5 by 5 to find the individual weight then you get the weight you found and multiply it by 24 to get the weight of twenty four bricks

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What is 2 + 2, times 12, plus 9, divided by 1200, multiplied by 6, minus 12,000,000, divided by 4, plus 26, times 9, times 8, ti

vredina [299]

Answer:

78638.045 I hope this helped

8 0

3 years ago

Which function could be represented by the graph on the coordinate plane?

kodGreya [7K]

Answer:

$f(x)=a(x-h)^{2} -k$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2} +k$

where (h,k) is the vertex of the parabola

The axis of symmetry is equal to

$x=h$

In this problem the parabola open upward

so

the coefficient a is positive

The coordinates of the vertex will be $(h,-k)$ (the y-coordinate is negative)

so

the equation will be of the form

$f(x)=a(x-h)^{2} -k$

5 0

3 years ago

Read 2 more answers

Find an m > 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.

Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

$x^4-(3m+2)x^2+m^2=0$

$x^4+0x^3-(3m+2)x^2+0x+m^2=0$

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

$a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}$

$=\frac{0}{1}=0$

$\implies a=0----(1)$

$(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}$

$=\frac{-3m-2}{1}$

$3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2$

$-10b^2=-3m-2$

$\implies b^2=\frac{3m+2}{10}-----(2)$

$(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2$

$9b^4=m^2$

$9(\frac{3m+2}{10})^2=m^2$

$9(\frac{9m^2+4+12m}{100})=m^2$

$81m^2+36+108m=100m^2$

$-19m^2+108m+36=0$

$19m^2-108m-36=0$

$19m^2-114m+6m-36=0$

$19m(m-6)+6(m-6)=0$

$(19m+6)(m-6)=0$

$\implies m=-\frac{6}{19}\text{ or }m=6$

But m > 0,

Hence, the value of m is 6.

4 0

3 years ago

1/2 (x-4/5)=3/5

malfutka [58]

1/2x-2/5=3/5 (BTW I got 2/5 by reducing 4/10)
1/2x=7/5 (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5

14/5

I do free online math homework help tutoring if interested!

6 0

2 years ago

Which of the following is an arithmetic sequence?

gizmo_the_mogwai [7]

Hello,
Answer B

$a_{0} = -8\\ a_{n+1} = a_{n} +2$

6 0

2 years ago