All categories

3 years ago

find the sum of even numbers between 1001 and 10,000 (Arithmetic progressions) DO STEP BY STEP PLEASE

Mathematics

1 answer:

love history [14]3 years ago

7 0

Step-by-step explanation:

arithmetic progression

even numbers between 1001 and 10000

1002,1004,.......9998

Tn=a+(n-1)d

Tn = 9998 last term in the progression of even numbers

a = 1002 first term

d = 2 distance

9998=1002+(n-1)(2)

8996=2n-2

8998=2n

n = 4499 the number of terms

sum = n/2 (a+Tn) = 4499/2(1002+9998)

= (4499/2)(11000) = 24744500

Logic:

notice what happens when you add the first and last terms

1002+9998=11000

1004+9996=11000

.......

You might be interested in

VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.

melomori [17]

Answer:

It is D Because I'm soo Smart And the Question is easy

5 0

3 years ago

A rectangle is divided into five triangles as shown. Noa h sa ys that the area of triangle A ls half the area of triangle B. Do

makkiz [27]

Answer:

SLLSSLSLSL

Step-by-step explanation:

ipouoooooooo

5 0

3 years ago

Read 2 more answers

“ I need help with these . I’m trying my best so can u help .

Debora [2.8K]

Can not see it sorry

5 0

3 years ago

Read 2 more answers

"What is the length of stack J K with bar on top ? Round to the nearest tenth of a unit.

Sedaia [141]

Stance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(3,5)(7,3)
d = sqrt (7 - 3)^2 + (3 - 5)^2
d = sqrt 4^2 + (-2^2)
d = sqrt 16 + 4
d = sqrt 20
d = 4.47....rounded = 4.5

3 0

3 years ago

Read 2 more answers

A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig

Anika [276]

Answer: (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

$\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size = 463

$\mu=118\text{ minutes}$

$\sigma=65\text{ minutes}$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

$118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)$

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0

3 years ago

find the sum of even numbers between 1001 and 10,000 (Arithmetic progressions) DO STEP BY STEP PLEASE ​

find the sum of even numbers between 1001 and 10,000 (Arithmetic progressions) DO STEP BY STEP PLEASE