So:
(x-4)(x+2) / (x-4)(x+4)
We cancel out the x - 4:
(x+2)/(x+4)
Restrictions: x ≠ 4, x ≠ -4
The answer to the question
<h3>
Answer: Choice D) </h3>
Work Shown:
We must require that 
and 
to avoid having 0 in the denominator. This is why choice D is the answer.
Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Answer:
I don't know, because i really don't know
