The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
Read more about function intervals at:
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3.14*d
3.14*12= 37.68
Rounded to the nearest hundredth would be 37.7
<h2>236.59cm²</h2>
Step-by-step explanation:
<h3>Area of octagon = 2(1+√2)a²</h3><h3> = 2(1+√2)7²</h3><h3> = 236.59cm²</h3>
<h2>MARK ME AS BRAINLIST</h2>
Answer:
see below
Step-by-step explanation:
1) Slope from P to Q is F/E
2) Definition of slope
3) F'/E' = F/E
Answer:
142%
Step-by-step explanation:
i may be wrong but hopefully im not!!
