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kirill [66]
3 years ago
11

S. At Food Lion, 28 of every 35 jars of peanut butter on the shelves are creamy peanut butter. What percent of the jars of peanu

t butter are not creamy?​
Mathematics
2 answers:
Alborosie3 years ago
7 0

Answer:

7/35 or 20% of the jars are not creamy

ANEK [815]3 years ago
6 0

Answer:

20%

Step-by-step explanation:

To find the percent of NOT creamy:

35(total peanut butter) - 28(creamy) = 7

Question now is: 7 is what % of 35?

Formula = a(part) = p(percent)*w(whole)

p = a/w

7/35 = 0.2

0.2 is a decimal so multiply by 100 to get 20%

The answer should be 20% so I hope this helps!

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valentina_108 [34]

<u>Answer:</u> The minuend is 20000

<u>Step-by-step explanation:</u>

To calculate the minuend, we use the equation:

\text{Subtrahend}=\text{Minuend-Difference}

We are given:

Difference between the two numbers = 7194

Subtraend = 12806

Putting values in above equation, we get:

\text{Minuend}=12806+7194\\\\\text{Minuend}=20000

Hence, the minuend is 20000

3 0
3 years ago
Use the distributive property to remove the parentheses.<br> (v-2)9
Sunny_sXe [5.5K]

Answer:

9v-18

Step-by-step explanation:

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5 0
3 years ago
Maths Problem. I can't quite explain it, could you help please? Thanks for every good answer. All shown on the picture :)
Nimfa-mama [501]

This is something you would do through trial and error. At least, that's the approach I took. I'm not sure if there is any algorithm to solve. The solution I got is shown in the attached image below. There are probably other solutions possible. The trick is to keep each number separate but not too far away so that the other numbers to be filled in later don't get too crowded to their neighbor.

Side note: any mirror copy of what I posted would work as well since you can flip the page around and it's effectively the same solution.

7 0
4 years ago
Please find answer. ​
Anuta_ua [19.1K]

Answer:

Again, the answer is (1,-2)

Step-by-step explanation:

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8 0
3 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
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