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blondinia [14]
3 years ago
5

Calculate the mass of 29.6 L of fluorine gas at STP.

Chemistry
1 answer:
Lunna [17]3 years ago
7 0

Answer:

Mass = 25.08 g

Explanation:

Given data:

Volume of fluorine = 29.6 L

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Mass of fluorine = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

n = PV/RT

n = 1 atm × 29.6 L / 0.0821 atm.L/ mol.K × 273.15 K

n = 1.32 mol

Mass of fluorine:

Mass = number of moles × molar mass

Mass = 1.32 mol ×19 g/mol

Mass = 25.08 g

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<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

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             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

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