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Gelneren [198K]

2 years ago

9

Lead(II) chromate, PbCrO4, is a yellow paint pigment (called chrome yellow) prepared by a precipitation reaction. In a preparati

on, 52.5 g of lead(II) chromate is obtained as a precipitate. How many moles of PbCrO4 is this

1 answer:

Roman55 [17]2 years ago

8 0

Answer:

n = 0.1624 moles

Explanation:

$n=\frac{m}{M} \\n=\frac{52.5}{323.1937} \\n= 0.1624 mol$

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To investigate the reactivity of metals a student uses four metals. Each time they added 1 g of the metal to 25 cm³ of sulfuric

Mazyrski [523]

Answer:

Volume of the sulfuric acid (25cm³), same mass of each metal (1g)

Explanation:

In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.

In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.

5 0

2 years ago

grigory [225]

Answer:

B - (C , Al, P, Cl)

Explanation:

How I got this answer was by looking at my periodic table it shows you how much it contains by the Atomic number.

Atomic number on C (Carbon) is- 6

Atomic number on Al (Aluminum) is - 13

Atomic number on P (Phosphorus) is - 15

Atomic number on Cl (Chlorine) is - 17

Now it says least to greatest and the other options are wrong I did the work for you hope this helps :)) I also had this project you didnt ask but the answer for the The Lesson are {B E M S} which as the code numbers are gonna be -7494- Im glad to help if you need more help I will give you the other answers as well :) !

3 0

3 years ago

David went shopping with his mom for house renovations supplies. They were looking for materials that would conduct electricity.

maxonik [38]

Answer:

this will copper this is correct answer

7 0

2 years ago

How many total atoms are in 0.690 g of P2O5?

Dmitry_Shevchenko [17]

M P₂O₅ = 31g×2 + 16g×5 = 142g/mol

1 mole of P₂O₅ contains 5 moles of atoms
5 moles of atoms = 30,01×10²³ a.

142g ----------- 30,01×10²³ a.
0,69g ---------- X
X = (0,69×30,01×10²³)/142
X = 0,14626×10²³ = 1,4626×10²² atoms

:)

8 0

3 years ago

2. Nitrogen has two naturally occurring

kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0

2 years ago