Question

Lead(II) chromate, PbCrO4, is a yellow paint pigment (called chrome yellow) prepared by a precipitation reaction. In a preparation, 52.5 g of lead(II) chromate is obtained as a precipitate. How many moles of PbCrO4 is this

Answer 1

Answer:

n = 0.1624 moles

Explanation:

$n=\frac{m}{M} \\n=\frac{52.5}{323.1937} \\n= 0.1624 mol$