Question

Please help me with my algebra work i need help

Answer 1

Answer:

$y = \frac{4}{3}x - 13$

Step-by-step explanation:

The equation for a line in slope-intercept form is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept. This means that the slope of $y = \frac{4}{3}x + 5$ is 4/3.

We would like to find a line parallel to $y = \frac{4}{3}x + 5$ which passes through the point (12, 3). Any parallel line must have the same slope, so the equation for the new line will be $y = \frac{4}{3}x + b$ for some number $b$. We know that $y$ must be equal to 3 when $x$ is equal to 12, so 3 = (4/3)(12) + b. This means that 3 = 16 + b, so b = -13.

Therefore, the equation for the parallel line is $y = \frac{4}{3}x - 13$.