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erma4kov [3.2K]
3 years ago
14

Please help me with my algebra work i need help

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer:

y = \frac{4}{3}x - 13

Step-by-step explanation:

The equation for a line in slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept. This means that the slope of y = \frac{4}{3}x + 5 is 4/3.

We would like to find a line parallel to y = \frac{4}{3}x + 5 which passes through the point (12, 3). Any parallel line must have the same slope, so the equation for the new line will be y = \frac{4}{3}x + b for some number b. We know that y must be equal to 3 when x is equal to 12, so 3 = (4/3)(12) + b. This means that 3 = 16 + b, so b = -13.

Therefore, the equation for the parallel line is y = \frac{4}{3}x - 13.

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