To factor both numerator and denominator in this rational expression we are going to substitute
with
; so
and
. This way we can rewrite the expression as follows:
Now we have two much easier to factor expressions of the form
. For the numerator we need to find two numbers whose product is
(30) and its sum
(-11); those numbers are -5 and -6.
and
.
Similarly, for the denominator those numbers are -2 and -5.
and
. Now we can factor both numerator and denominator:
Notice that we have
in both numerator and denominator, so we can cancel those out:
But remember than
, so lets replace that to get back to our original variable:
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is
ANSWER
c. Domain: [0,18]
Range: [0,360]
EXPLANATION
The domain refers to the values of x for which the function is defined.
The given straight line graph is defined for x=0 to x=18.
Hence the domain is [0,18]
The range refers to the values of y for which x is defined.
The graph is defined for y=0 to y=360.
The range is [0,360]
Answer:
so just successive powers of 2
Step-by-step explanation:
1, 3, 7, 15, 31, 63, _? Add successive powers of 2 to the number: 1+2=3; 3+4=7; 7+8=15; 15+16=31; 31+32=63; 63+64=127.
Vertex (-3,1)
No xinters
Y-inter (0,37)
Answer:
c
Step-by-step explanation:
just c because i was in this situation