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2 years ago

Felix said quadrilateral ABCD is a parallelogram because BE = DE. What was his error?

Mathematics

1 answer:

Kamila [148]2 years ago

7 0

Answer:

There is no angle E in the quadilateral presented in the question. Also, the angles he used are not on opposite side.

Step-by-step explanation:

To classify a quadrilateral is a parallelogram, a quadrilateral with both pairs of opposite sides must be parallel or congruent, that is in a quadrilateral ABCD, angle AB must equal CD and angle AD must equal BC.

Hence, when Felix said quadrilateral ABCD is a parallelogram because of BE = DE. His error was that "there is no angle E in the quadrilateral presented in the question and the angle he used are not on opposite side"

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valentina_108 [34]

Answer:

E. This polynomial could be factored by using grouping or the perfect squares methods.

Step-by-step explanation:

x^2 + 2x + 1

There is no greatest common factor

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We can factor this by grouping

x^2 + 2x + 1

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Factor out x+1

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1. To the nearest tenth of a centimeter, how tall is a

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A plumber is fitting A water pipe that is 3/4 foot long on to a water pipe that is 2/12 foot long.How long will the finish pipe

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3 years ago

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Exhibit 9-2 The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the cu

Diano4ka-milaya [45]

Answer:

At a .05 level of significance, it can be concluded that the mean of the population is significantly more than 3 minutes.

Step-by-step explanation:

We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes.

At the null hypothesis, we test if the mean is of at most 3 minutes, that is:

$H_0: \mu \leq 3$

At the alternative hypothesis, we test if the mean is of more than 3 minutes, that is:

$H_1: \mu > 3$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

3 is tested at the null hypothesis:

This means that $\mu = 3$

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This means that $n = 100, X = 3.1, \sigma = 0.5$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3.1 - 3}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 3.1, which is 1 subtracted by the p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

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The p-value of the test is of 0.0228 < 0.05, meaning that the is significant evidence to conclude that the mean of the population is significantly more than 3 minutes.

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3 years ago

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r-ruslan [8.4K]

Answer:

The equation has an Inifinite amount of solutions

Step-by-step explanation:

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First use the distributive property of multiplication -

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6g cancels out from both sides of the equation -

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Hope this helped! :)

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