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Tju [1.3M]
2 years ago
14

Ahnna owes her parents $200. Ahnna owes her best friend $20. Ahnna's net worth is $50. Find the value of Ahnna's assets.

Mathematics
1 answer:
sladkih [1.3K]2 years ago
6 0

Answer:

$270.

Step-by-step explanation:

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The ratio for 12 packs at 4 for $10
Lorico [155]
I think the ratio is for for every 4 packs it cost 10 dollars so in all it would cost 30 dollars
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3 years ago
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Find parametric equations for the line parallel to r=(6,-8) and passing through P(9,-1)
fgiga [73]

Answer:

x=6t+9 y=-8-1

Step-by-step explanation:

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3 years ago
What is the sum of the matrices shown below?
damaskus [11]

Answer:

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]

Step-by-step explanation:

To add matrices, we add the corresponding components.

The given matrices is

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]

We add the corresponding components to get;

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}3+6&9+0\\5+-8&-2+4\end{array}\right]

We simplify to get:

\left[\begin{array}{cc}3&9\\5&-2\end{array}\right] +\left[\begin{array}{cc}6&0\\-8&4\end{array}\right]=\left[\begin{array}{cc}9&9\\-3&2\end{array}\right]

5 0
3 years ago
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A teacher surveys a sample of students from Lake Middle School. He asks the students where they’d like to go for a field trip. H
Fittoniya [83]

Answer:

210 student's

Step-by-step explanation:

80 students chose the aquarium.

60 students chose the science center.

30 students chose the planetarium.

40 students chose the farm.

The students can't vote for more than one place, so you just add all the numbers together.

80 + 60 + 30 + 40 = 210 students

8 0
3 years ago
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Help please 4, 5, 6.......
Assoli18 [71]

4.  Supplementary angles together make a straight line (two right angles).  So BOE is supplementary to BOC

Answer: ∠BOE

5. Distance and midpoint between (4,-2), (6,8)

d = \sqrt{ (6-4)^2 + (8 - -2)^2} = \sqrt{2^2+10^2}=\sqrt{104}=2 \sqrt{26}

midpoint

\left(\dfrac{4 + 6}{2}, \dfrac{-2 + 8}{2} \right) = (5, 3)

Answer: distance 2√26, midpoint  (5, 3)

6.That's a rectangle oriented parallel to the axes, width parallel to the x axis of 7 - -3 = 10 and length along y of  1 - - 4 = 5, so an area of 10(5)=50

Answer: 50

5 0
3 years ago
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