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gtnhenbr [62]
3 years ago
14

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis

tance in 4 h. Car A traveled 22 mph faster than Car B. How fast did Car A travel? (The formula R⋅T=D , where R is the rate of speed, T is the time, and D is the distance can be used.)
Mathematics
2 answers:
MArishka [77]3 years ago
3 0
If Car A's speed is x, then Car B's speed is x-22. Using the formula, we get that the distance is the same in both, so 4*(x-22)=D and 2.4*x=D due to that we plug 2.4 and 4 in for T and x-22 and x for R. Since they both equal D, we can write it as 2.4*x=4*(x-22). Using the distributive property, we get 4*(x-22)=4x-88=2.4*x. Subtracting 2.4*x from both sides as well as adding 88, we get 1.6*x=88. Dividing both sides by 1.6, we get 88/1.6=55= x=Car A's speed
amm18123 years ago
3 0

wait so what is the answer then

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Can someone explain how you solve proofs?
kap26 [50]

Answer:

Yeahh

Step-by-step explanation:

Write the statement in one side and give the reasons on other side.

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6 0
3 years ago
An unknown number w is 30 more than an unknown number p. The number w is also p less than 5
AleksandrR [38]
The problem statement gives rise to two equations.
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Add these two equations to get
  2w = 35
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The unknown number w is 17.5.
The unknown number p is -12.5.
7 0
3 years ago
In 2010, the population of a town was 8500. The population decreased by 4.5% each year.
Soloha48 [4]

Answer:

This is a problem in exponential decay.

a) If a town's population decreases by 4.5% every year that also means that the town's population decreases by a factor of .955 each year.  (1 - .045 = .955)

So, after 5 years, the town's population is:

8,500 * .955^5 which equals 6,752.

So, basically, after t years, the town's population equals

8,500 * .955^t  where t is the number of years that have passed since the year 2010.

b) population = 8,500 * .955 ^ (number of years since 2010)

7,000 / 8,500  = .955 ^ (number of years since 2010)

0.8235294118  = .955 ^ (number of years since 2010)

To solve for (number of years since 2010) we take logs of both sides

log (0.8235294118 ) = number of years since 2010 * log(.955)

-0.0843208857  = number of years since 2010 * -0.0199966284

-0.0843208857  / -0.0199966284  = number of years since 2010

4.2167551422  = number of years since 2010

So, population = 7,000 when the year is 2014.2167551422

Or about  2.6 months into 2014

(YES, it's just that "easy")  LOL

Step-by-step explanation:

6 0
3 years ago
What is the total finance charge for a $4,250 loan at 13.25% interest compounded monthly for 24 months?
Rom4ik [11]
Since only the principal value, interest rate and interest period are given, we can deduce that "finance charge" only includes the interest to be paid at the end of the term. This can be obtained by subtracting the principal value from the future value which we will solve for.

The future value can be solved by using the following compound interest formula:

Let:
F = Future value
P = Principal value
r<span> = annual interest rate </span>
n<span> = number of times that interest is compounded per year</span>
t<span> = number of years</span>

F = P(1 + r/n)^nt

Substituting the given values:
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Subtracting P from F:
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Therefore the finance charge is $1,281.54
6 0
3 years ago
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Effectus [21]

Answer:

f(x) = 4/7x + 20/7

Step-by-step explanation:

If we were to graph this function, we would see that the two points would be, (-5, 0), and (2, 4). First, we have to find the slope, which is equal to:

<u>(first y-coordinate - the second y coordinate)</u>

(first x-coordinate - second x coordinate)

= <u>(0 - 4)</u>

   (-5 - 2)

= -4/-7 = 4/7. now, we multiple -5 by 4/7 and get -20/7. we have to add 20/7.

Thus, the answer is f(x) = 4/7x + 20/7

5 0
3 years ago
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