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3 years ago

A telescope is on sale for 30% off. The discount was $90. What was the original price?

Mathematics

1 answer:

ahrayia [7]3 years ago

3 0

Answer:

117

Step-by-step explanation:

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1. Laura earns $115 a month babysitting. If she saves all of the

TEA [102]

Answer:

Laura will have exactly $72.00 after purchasing the bicycle.

Step-by-step explanation:

We are given that Laura ends $115 per month of babysitting.

We also learn that she wants to save her money from June and July, which means she wants to save her money over a period of two months.

Therefore, she will earn $115 twice.

$\displaystyle{\$115 \times 2 = \$230}$

Then, she wants to purchase a bicycle that costs $158, so we need to subtract the cost of the bicycle from her total earnings.

$\$230 - \$158 = \$72$

Therefore, Laura will have exactly $72.00 remaining after her purchase.

8 0

3 years ago

The value of a car is $18,000 and is depreciating 6% each year. What will the value of the car be in 7 years?

Fudgin [204]

Answer:

$11672.60

Step-by-step explanation:

<u>Given:</u>

Initial value a = $18000
Rate of depreciation 6% or b = 1 - 0.06 = 0.94
Time x = 7 years

<u>Find the value of the car in 7 years:</u>

y = abˣ
y = 18000*0.94⁷ = 11672.60

4 0

3 years ago

A farmer is planting some marigolds in a row. The row is 2 yards long. The flowers must be spaced ⅓ yard apart so they will have

Mrac [35]

Answer:

Step-by-step explanation:

8 0

3 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

1 year ago

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago