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SSSSS [86.1K]
4 years ago
11

(05.02)One triangle on a graph has a vertical side of 5 and a horizontal side of 11. Another triangle on a graph has a vertical

side of 15 and a horizontal side of 33.
Could the hypotenuses of these two triangles lie along the same line?

No, because they need to be the same size
No, because they are not similar triangles
Yes, because all triangles can fit along this line
Yes, because they are similar triangles
Mathematics
2 answers:
Vladimir [108]4 years ago
7 0

Answer:

The answer is the option

Yes, because they are similar triangles

Step-by-step explanation:

we know that

The first and the second triangle are right triangles

The hypotenuses of these two triangles could lie along the same line,  if the two triangles were similar

Verify if the triangles are similar

Remember that

If two triangles are similar then

the ratio of their corresponding sides is equal

so

\frac{5}{15}=\frac{11}{33}

simplify

\frac{1}{3}=\frac{1}{3} --------> is rue

therefore

the triangles are similar

and the answer is

Yes, because they are similar triangles

Andrew [12]4 years ago
4 0
Yes because they are similar triangles
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2/3 ÷ 4/7 Perform the calculation
Ad libitum [116K]

Answer:

7/6

Step-by-step explanation:

With fractional division you should keep the first fraction, get the reciprocal of the second faction, and switch the division to a multiplication.

2/3 ÷ 4/7

= 2/3 x 7/4

= 14/12

= 7/6

4 0
3 years ago
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A family has two cars. During one particular week, the first car consumed 15 gallons of gas and the second consumed 35 gallons o
bezimeni [28]

<u>Answer: </u>

Fuel efficiencies of two cars in that week are 20 miles per gallon and 40 miles per gallon.

<u>Solution: </u>

Let the two cars of family be A and B.

Gas consumed by car A = 15 gallons

Gas consumed by car B = 35 gallons

Let’s assume number of miles car A drove in that week = x miles

Assume number of miles car B drove in that week = y miles

Given that two cars drove a combine of 1700 miles in that week.

So we can say,

x + y = 1700  --- eqn (1)

Fuel efficiency of any car = \frac{\text { Number of miles covered }}{\text { gallons of gas consumed }}

So fuel efficiency of car A = \frac{x \text { miles }}{15 \text { gallons }}

And fuel efficiency of car B = \frac{y \text { miles }}{35 \text { gallons }}

Given that sum of efficiencies of two cars = 60 miles per gallons.

\frac{x}{15}+\frac{y}{35}=60

\frac{35 x+15 y}{35 \times 15}=60

On cross-multiplication we get,

5(7x +3y) = 15 \times 35 \times 60

7x +3y = 6300  --------- eqn (2)  

Now we have following two equations and two variable to be determine.  

x + y = 1700       --------  (1)

7x +3y = 6300     --------  (2)

On modifying equation (1) we get

y = 1700 -  x        --------(3)

On substituting value of y from equation (3) in equation (2) we get

7x + 3(1700-x) = 6300

7x + 5100 – 3x = 6300

4x = 6300 – 5100  

4x = 1200

x = 300

Substituting value of x in equation 3 to get value of y

y = 1700 – 300 = 1400

Fuel efficiency of car A = \frac{x}{15} = \frac{300}{15} = 20 miles per gallon

Fuel efficiency of car B = \frac{y}{35} = \frac{1400}{35} = 40 miles per gallon.

Hence fuel efficiencies of two cars in that week are 20 miles per gallon and 40 miles per gallon.

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Estimate the solution to the system of equations y=-2x-5 and y=2x-2
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Answer: x = -3/4  , y = -7/2

Step-by-step explanation:

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3 years ago
Divide Rs.300 between A and B in the ratio2:3
kherson [118]

The value of 300 is divided into 120 and 180 in the ratio of 2:3.

<u>Step-by-step explanation</u>:

  • The total value is 300.
  • This total of 300 should be divide in the ratio of 2:3.

Let us assume that the common factor be x in the ratio.

  • The value of the part A is 2x.
  • The value of the part B is 3x.

It is known that, 2x + 3x = 300

⇒ 5x = 300

⇒ x = 300/5

⇒ x =60.

<u>To find the values of A and B :</u>

A= 2x

⇒ 2(60)

⇒ 120

B= 3x

⇒ 3(60)

⇒ 180

The value of 300 is divided into 120 and 180 in the ratio of 2:3.

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The answer would be

<em>H. 30</em>

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