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3 years ago

Plz help me plzz i need it

Mathematics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

second one

Step-by-step explanation:

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Find the equation of the line that passes through the points (3,-2) and (6,-8)

Karolina [17]

Answer:

$2x + y = 4$

Step-by-step explanation:

The two-point form of the equation of a line is:

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)$

We have:

x1 = 3

y1 = -2

x2 = 6

y2 = -8

Plug in all the values where they belong in the equation above.

$y - (-2) = \dfrac{-8 - (-2)}{6 - 3}(x - 3)$

Simplify.

$y + 2 = \dfrac{-6}{3}(x - 3)$

$y + 2 = -2(x - 3)$

$y + 2 = -2x + 6$

$2x + y = 4$

3 0

2 years ago

How many different towers can you make using one red, one blue and one yellow block?

icang [17]

You can make 6 different towers. If red was at the bottom, there'd be two different possibilities for that: red, yellow, blue, and red, blue, yellow. Same for if blue was at the bottom: blue, red, yellow, and blue, yellow, red. Yellow also applies: yellow, red, blue, and yellow, blue, red. 3*2=6, so 6 possible towers.

7 0

3 years ago

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$