Find the area of the following shape. you must show all work to receive credit
1 answer:
Answer with explanation:
Join AC and FG.Draw BN ⊥ AC.
AC=9 units, BN=3 units, CG=3 units, GF=6 units, FE=4 units,GD=3 Units
Area (ΔABC)
Area of Trpzoid
![=\frac{1}{2} \times [\text{Sum of Parallel sides}] \times [\text{Perpendicular Distance between them}]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5B%5Ctext%7BSum%20of%20Parallel%20sides%7D%5D%20%5Ctimes%20%5B%5Ctext%7BPerpendicular%20Distance%20between%20them%7D%5D)
Area of Trpzoid ACGF
![=\frac{1}{2} \times [AC+GF]\times CG\\\\=\frac{1}{2} \times [9+6]\times 3\\\\=\frac{45}{2}\text{Square units}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5BAC%2BGF%5D%5Ctimes%20CG%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5B9%2B6%5D%5Ctimes%203%5C%5C%5C%5C%3D%5Cfrac%7B45%7D%7B2%7D%5Ctext%7BSquare%20units%7D)
Area of Trpzoid FGDE
![=\frac{1}{2} \times [FE+GD]\times FG\\\\=\frac{1}{2} \times [3+4]\times 6\\\\=21\text{Square units}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5BFE%2BGD%5D%5Ctimes%20FG%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%5B3%2B4%5D%5Ctimes%206%5C%5C%5C%5C%3D21%5Ctext%7BSquare%20units%7D)
Area of given shape
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Answer:
13
Step-by-step explanation:
Y would be 18 because 260 * .2 = 52, so 90 * .2 = 18.
To find the common ratio
divide by the previous numb/number beside it:

so
The 8 oz for $1.50
Cost/Measurements
1 pound = 16 onces
$2.50/16 oz= about 16 cents per ounce
$1.50/8 oz= about 19 cents peronce
Answer:
9586.232772
$4000×1.06( to the power of 15)=9586.232772