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Papessa [141]
4 years ago
11

Find the area of the following shape. you must show all work to receive credit

Mathematics
1 answer:
choli [55]4 years ago
7 0

Answer with explanation:

Join AC and FG.Draw BN ⊥ AC.

AC=9 units, BN=3 units, CG=3 units, GF=6 units, FE=4 units,GD=3 Units

Area (ΔABC)

              =\frac{1}{2} \times {\text{Base}} \times \text{Height}\\\\=\frac{1}{2} \times {BN} \times {AC}\\\\=\frac{1}{2} \times 9 \times 3\\\\=\frac{27}{2}\text{Square units}  

Area of Trpzoid

            =\frac{1}{2} \times [\text{Sum of Parallel sides}] \times [\text{Perpendicular Distance between them}]

Area of Trpzoid ACGF

         =\frac{1}{2} \times [AC+GF]\times CG\\\\=\frac{1}{2} \times [9+6]\times 3\\\\=\frac{45}{2}\text{Square units}

Area of Trpzoid FGDE

        =\frac{1}{2} \times [FE+GD]\times FG\\\\=\frac{1}{2} \times [3+4]\times 6\\\\=21\text{Square units}

Area of given shape

               =\frac{27}{2}+\frac{45}{2}+21\\\\=36+21\\\\=57 \text{Square units}

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A^4 + 2b OVER a; if a =3 and b = 12
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Jeremy has 50 ft of fencing to enclose a rectangular-pen for his dog. He plans on using a side of his house for one side of the
kotykmax [81]

The dimensions such as length is 18 and width is 16 or length is 32 and width is 9 will produce an enclosed area of 288ft.

<h3>What is the dimension of length and width?</h3>

We know that,

P = l + 2w

50 = l + 2w

50 - 2w = l

A = l x w

288 = (50 - 2w)w

288 = 50w -2w²

2w² - 50w + 288

By dividing throughout by 2

w² - 25w + 144

This is in quadratic equation form.

By applying quadratic formula,

w = (-(-25) ± \sqrt{(-25)^{2}-4*1*144) / 2

w = (-(-25) ± 7)/2

w1 =  (-(-25) + 7)/2

w1 = (25 + 7) / 2

w1 = 16

w2 =  (-(-25) - 7)/2

w2 = (25 - 7) / 2

w2 = 9

By substituting the values in eq1,

A = l x w

if w = 16

288 = l x 16

l = 288/16

l = 18

if w = 9

288 = l x 9

l = 288/9

l = 32

The dimensions will be length is 18 and width is 16 or length is 32 and width is 9.

To learn more about area of rectangle refer to :

brainly.com/question/25292087

#SPJ1

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