-5/13
Formula: Y2-Y1/X2-X1
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
315
Step-by-step explanation:
If one gallon of gas can give you 45 miles, than multiple 45 ( the miles ) times 7 (the gallons of gas) and you will have your answer :)
Answer:
see below
Step-by-step explanation:
Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.
Let's choose x=0 and x=4. Then the corresponding y-values are ...
y = 2·0 = 0 . . . . . point (x, y) = (0, 0)
y = 2·4 = 8 . . . . . point (x, y) = (4, 8)
These are graphed below.