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3 years ago

What is the value of x? 7 7sqrt2 14 14sqrt2

Mathematics

1 answer:

Nutka1998 [239]3 years ago

3 0

Answer:

Step-by-step explanation:

sin45=(7√2)/x

x=(7√2)/(sin45)=14

hope this help

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2. Explain the relationship between depression and heart disease.

vredina [299]

Answer:

People with depression may have uncommonly sticky platelets, the tiny cells that cause blood to clot. In patients with heart disease, this can accelerate atherosclerosis (hardening of the arteries) and increase the chance of heart attack. Some studies show that treating depression make platelets less sticky again.

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2 years ago

Read 2 more answers

Find f(-9) for f(x)= -3x^2-20

lions [1.4K]

Answer:

-263

Step-by-step explanation:

replace x by -9

5 0

2 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

Are these answers correct? If not, what would the answers be?

Ludmilka [50]

Yes you have the correct answers for each of the four problems. Nice work.

For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
c = continuous

7 0

3 years ago

Find y when x = 2 <br><br>y = 30 - 2x

lisabon 2012 [21]

Y = 30 - 2(2)
y= 30 - 4
y = 26

4 0

3 years ago